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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
 Posted - Nov 06 2010 : 05:38:28 AM
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pebe, what you said made no sense to me.
Dumb it down a little, please.
I'm using the 4011 IC Only, as of now.
In the diagram, pins 13,12,9,8,7,6,and 5 are all grounded.
How do i connect the negative terminal to the 7th pin ?
Also, how do i ground the circuit ?
Using ceramic disk capacitors ?
^^If anything i've said sounds extremly stupid, its cause im a complete beginner. ( ive said so , already.) |
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pebe
Nobel Prize Winner
United Kingdom
1078 Posts |
Posted - Nov 06 2010 : 06:23:30 AM
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My comments only refer to using the 4069.
If you are staying with the 4011 they don't apply. |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 06 2010 : 08:34:02 AM
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| Okay. Can you explain the other two questions I have ? |
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pebe
Nobel Prize Winner
United Kingdom
1078 Posts |
Posted - Nov 06 2010 : 08:45:20 AM
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| Connect the two 'ground' points together (pin5 and the bottom of C1) and connect the negative terminal of your battery to them. |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 06 2010 : 11:50:12 AM
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So, to ground the circuit we use capacitiors ?
Can we use a separate capacitor ?
What do you mean by the 'bottom' of C1?
Also, in the diagram pins 13,12,9,8,7,6 AND 5. Shouldn't all of these be grounded ?
Download Attachment:  time-delay-relay-ii_med.gif
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audioguru
Nobel Prize Winner
Canada
4218 Posts |
Posted - Nov 06 2010 : 2:18:15 PM
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All the grounds are simply connected together and also connect to the negative wire of the battery.
The ground symbol is used on a schematic to prevent ground wires running all over the schematic.
The circuit is not connected to earth.
It is obvious how C1 is connected.
But this circuit will not work unless you find a relay that uses an extremely low coil current or unless you add a transistor to drive the relay. |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 07 2010 : 12:30:48 AM
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I got the part about the relay. Will do so.
Is the positive terminal connected to the circuit in two places , or just to the 14th pin ? |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 07 2010 : 12:37:20 AM
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| Same for the negative terminal. Do i connect C1 and the grounded pins individually to the negative terminal, or should I connect the grounded pins to C1, and the whole thing to the negative terminal ? |
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audioguru
Nobel Prize Winner
Canada
4218 Posts |
Posted - Nov 07 2010 : 09:59:46 AM
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Can't you see that everything connected to the (+) terminal of the battery on the schematic are connected together?
Don't you understand that everything connected to a ground symbol on the schematic including the (-) terminal of the battery are connected together?
Since wire is almost a dead short and the current in this project is very low then it doesn't matter where things connect together. |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 07 2010 : 10:01:52 AM
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Sorry for being thick.
I see it now. |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 08 2010 : 07:50:16 AM
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How do you determine which pin is which ?
I placed it such that the writing was facing me, and started from the left.
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pebe
Nobel Prize Winner
United Kingdom
1078 Posts |
Posted - Nov 08 2010 : 09:08:03 AM
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Hold the chip with the pins facing away from you and the notch at the top.
Pin1 is then the left hand top pin. Count anticlockwise from there for the others. |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 08 2010 : 10:44:20 AM
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Here is the data sheet for the relay that Im using.
http://www.relay-rayex.com/downloadfiles/LEG_SERIES.pdf
Will this work with the current from the 4011 ?
its a small, new looking one, as suggested by audio guru.
If this WONT work, please, please, please, tell me a relay (from Rayex, t=since they're the only available ones)that will |
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audioguru
Nobel Prize Winner
Canada
4218 Posts |
Posted - Nov 08 2010 : 4:27:12 PM
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The pretty big and old Raytex relay needs 6V at 60mA to drive it so the CD4011 and the CD4069 will not work even if the gates and inverters are connected in parallel. Years ago I used a tiny relay that used 1/12th the current.
The circuit needs an added transistor and resistor to work.
I don't know how long you want the relay to be turned on but a little 9V alkaline battery will power it for only about 2 hours. |
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foggyeyes
Apprentece
United Arab Emirates
18 Posts |
Posted - Nov 25 2010 : 09:31:39 AM
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2 hours is good enough.
I am now using a 555 Timer Circuit (http://www.circuit-finder.com/categories/timer/425/time-delay-relay)
I connected all the components on a breadboard, but when I switch the circuit on, the LED (In place of the relay)turns on without any time delay. Also it stays on even when I switch the circuit off. I even removed the switch and it had no effect on the glowing LED.
Please HELP! |
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Time Delay Relay - Project
