|
audioguru
Nobel Prize Winner
Canada
4218 Posts |
 Posted - Jul 05 2011 : 3:03:38 PM
|
Your TIP42 transistor is shown upside-down. Its emitter must be more positive than its collector and its emitter is its output since it is an emitter-follower.
The output of your circuit feeds DC pulses to the transformer. The transformer works much better with AC when it is fed through a coupling capacitor like I show.
The battery needs a bypass capacitor.
I don't know if your transformer works well at 1kHz and I don't know if it is rated for at least 2W.
For 2W output the battery might have a load of 3W or 4W. A 4W load draws 444mA which a new little 9V battery can produce for only a few minutes. |
 |
|
power
