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                | kivdennNobel Prize Winner
 
      
 
                Uganda535 Posts
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                      |  Posted - Dec 23 2010 :  2:37:53 PM     
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                      | Am going to make a 24Volts version of this charger but am simply going to double the values of the components because I dont know how to find the appropriate values. If any body can help me before I begin, I highly appreciate. Thanks Dennis |  
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                | kivdennNobel Prize Winner
 
      
 
                Uganda535 Posts
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                      |  Posted - Dec 25 2010 :  07:14:05 AM     
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                      | I have made the circuit and it works fine but R4 to R8 get very hot in a short time. I used 162 ohms 2watts.Also resistor 2 seem not to be of the right value because the LED just blinks when adjusting for a higher voltage instead of completely turning off. Please help me find the right component values for these resistors. Thanks 
 Dennis
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                | audioguruNobel Prize Winner
 
      
 
                Canada4218 Posts
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                      |  Posted - Dec 25 2010 :  10:49:04 AM     
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                      | Don't you know that when you double the voltage across a resistor then its power (heating) is 4 times? If you double the voltage and double the value of the resistor then the power (heating) is double. |  
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                | kivdennNobel Prize Winner
 
      
 
                Uganda535 Posts
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                      |  Posted - Dec 25 2010 :  12:28:52 PM     
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                      | Thanks how about variable resistor? |  
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                | audioguruNobel Prize Winner
 
      
 
                Canada4218 Posts
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                      |  Posted - Dec 26 2010 :  09:39:41 AM     
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                      | quote:Originally posted by kivdenn
 
 Thanks how about variable resistor?
 
 
 Although a very expensive huge wire-wound variable resistor can be used, most variable resistors are for low power (less than 1/2W) and can control the conduction of some transistors that can get hot.
 
 Simply use ohm's Law to calculate the correct resistor value.
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                | erki112Apprentece
 
  
 
                11 Posts | 
                    
                      |  Posted - Mar 14 2011 :  09:20:00 AM     
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                      | I just made that circiut but the output voltage is around 9 v . when i connect it to charger ,it discharges the battery ,i tried to adjust pot but nothing happens ,the led always is light up. i use 2,5A 12V transformer which ac output is 13,1V. could someone help me wit that ,what would be the problem.                     Sorry for my bad english. 
 
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                | erki112Apprentece
 
  
 
                11 Posts | 
                    
                      |  Posted - Mar 15 2011 :  6:20:01 PM     
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                      | i found my problem the Q2 pins were changed . it charges the battery about 13,8 v .but how i test this circiut,because i dont know when the charging stops ,led dosent light up.i dont want to plow my battery . sorry for my bad english |  
                      | Edited by - erki112 on Mar 15 2011  6:20:31 PM
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                | awtApprentece
 
  
 
                Nigeria9 Posts
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                | erki112Apprentece
 
  
 
                11 Posts | 
                    
                      |  Posted - Mar 16 2011 :  3:47:46 PM     
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                      | i connected a fully charged battery to the charger but led didnt light up and voltage meter showed 15,6 ,battery started boiling, why didnt it turn of charging ,i tried to adjust pot but nothing happens. would the problem  in zener diode. i metered voltage from between r2 and D3 ,there was about 5,6-7V  wich changed when i turned pot . how much voltage there would be in the other side of D3. |  
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                | awtApprentece
 
  
 
                Nigeria9 Posts
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                      |  Posted - Mar 17 2011 :  04:40:14 AM       
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                      | Let's do it together, just few info from u will help. What did u use as: Q1 =
 Q2 =
 R4 =
 R5 =
 R7 =
 R8 =
 and d zener voltage of D3?
 
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                      | awotol
 www.simplecircuitsandprojects.com
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                | erki112Apprentece
 
  
 
                11 Posts |  | 
              
                | awtApprentece
 
  
 
                Nigeria9 Posts
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                      |  Posted - Mar 17 2011 :  1:47:57 PM       
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                      | Good, open up R5 and R8. Then short circuit out R7 while replacing R4 with 680ohm and R6 with 560ohm. Adjust R2 at 'high voltage cut off' |  
                      | awotol
 www.simplecircuitsandprojects.com
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                | erki112Apprentece
 
  
 
                11 Posts | 
                    
                      |  Posted - Mar 17 2011 :  2:46:13 PM     
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                      | im not good in enghlish,but do i have to remove R5 and R8.and bridge R7.and replace R4 with 680 ohm 2w resistor.and R6 with 560 ohm 1/4w resistor. and finaly set pot to the max and test |  
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                | awtApprentece
 
  
 
                Nigeria9 Posts
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                | awtApprentece
 
  
 
                Nigeria9 Posts
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                      |  Posted - Mar 17 2011 :  3:58:16 PM       
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                      | it doesn't matter, it will work. i only suggested that one with lesser wattage to reduce the cost. |  
                      | awotol
 www.simplecircuitsandprojects.com
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