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 Automatic 12V Lead Battery Charger
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kivdenn
Nobel Prize Winner

Uganda
535 Posts

Posted - Dec 23 2010 :  2:37:53 PM  Show Profile  Reply with Quote
Am going to make a 24Volts version of this charger but am simply going to double the values of the components because I dont know how to find the appropriate values. If any body can help me before I begin, I highly appreciate. Thanks Dennis
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kivdenn
Nobel Prize Winner

Uganda
535 Posts

Posted - Dec 25 2010 :  07:14:05 AM  Show Profile  Reply with Quote
I have made the circuit and it works fine but R4 to R8 get very hot in a short time. I used 162 ohms 2watts.Also resistor 2 seem not to be of the right value because the LED just blinks when adjusting for a higher voltage instead of completely turning off. Please help me find the right component values for these resistors. Thanks

Dennis
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audioguru
Nobel Prize Winner

Canada
4218 Posts

Posted - Dec 25 2010 :  10:49:04 AM  Show Profile  Reply with Quote
Don't you know that when you double the voltage across a resistor then its power (heating) is 4 times? If you double the voltage and double the value of the resistor then the power (heating) is double.
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kivdenn
Nobel Prize Winner

Uganda
535 Posts

Posted - Dec 25 2010 :  12:28:52 PM  Show Profile  Reply with Quote
Thanks how about variable resistor?
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audioguru
Nobel Prize Winner

Canada
4218 Posts

Posted - Dec 26 2010 :  09:39:41 AM  Show Profile  Reply with Quote
quote:
Originally posted by kivdenn

Thanks how about variable resistor?


Although a very expensive huge wire-wound variable resistor can be used, most variable resistors are for low power (less than 1/2W) and can control the conduction of some transistors that can get hot.

Simply use ohm's Law to calculate the correct resistor value.
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erki112
Apprentece

11 Posts

Posted - Mar 14 2011 :  09:20:00 AM  Show Profile  Reply with Quote
I just made that circiut but the output voltage is around 9 v . when i connect it to charger ,it discharges the battery ,i tried to adjust pot but nothing happens ,the led always is light up. i use 2,5A 12V transformer which ac output is 13,1V. could someone help me wit that ,what would be the problem. Sorry for my bad english.

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erki112
Apprentece

11 Posts

Posted - Mar 15 2011 :  6:20:01 PM  Show Profile  Reply with Quote
i found my problem the Q2 pins were changed . it charges the battery about 13,8 v .but how i test this circiut,because i dont know when the charging stops ,led dosent light up.i dont want to plow my battery . sorry for my bad english

Edited by - erki112 on Mar 15 2011 6:20:31 PM
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awt
Apprentece

Nigeria
9 Posts

Posted - Mar 16 2011 :  06:35:06 AM  Show Profile  Visit awt's Homepage  Reply with Quote
it is possible that the battery has not reached its 'high voltage cut off' already preset with R2. connect a voltage meter to the battery and adjust R2 when the battery reaches high voltage (say 13.8V or check the battery manufacturer's sheet) till the LED light up.

you can check here for another nice charger: http://www.simplecircuitsandprojects.com/circuits/lead-acid-battery-charger.html

awotol
www.simplecircuitsandprojects.com
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erki112
Apprentece

11 Posts

Posted - Mar 16 2011 :  3:47:46 PM  Show Profile  Reply with Quote
i connected a fully charged battery to the charger but led didnt light up and voltage meter showed 15,6 ,battery started boiling, why didnt it turn of charging ,i tried to adjust pot but nothing happens. would the problem in zener diode. i metered voltage from between r2 and D3 ,there was about 5,6-7V wich changed when i turned pot . how much voltage there would be in the other side of D3.
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awt
Apprentece

Nigeria
9 Posts

Posted - Mar 17 2011 :  04:40:14 AM  Show Profile  Visit awt's Homepage  Reply with Quote
Let's do it together, just few info from u will help. What did u use as:
Q1 =
Q2 =
R4 =
R5 =
R7 =
R8 =
and d zener voltage of D3?

awotol
www.simplecircuitsandprojects.com
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erki112
Apprentece

11 Posts

Posted - Mar 17 2011 :  10:31:15 AM  Show Profile  Reply with Quote
Q1 =bt136 triac http://www.oomipood.ee/?t=k_ki&i=1081316
Q2 =brx49 https://www.elfa.se/elfa3~ee_et/elfa/init.do?item=72-030-14&toc=0
R5,R7,R8,R4 =resistor 82R 2W http://www.oomipood.ee/?t=k_ki&i=2W%2082R D3 =Z-DI 5.6V 0.4W http://www.oomipood.ee/?t=k_ki&i=0.4W%205V6
i added links where i bought these.

Edited by - erki112 on Mar 17 2011 11:18:40 AM
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awt
Apprentece

Nigeria
9 Posts

Posted - Mar 17 2011 :  1:47:57 PM  Show Profile  Visit awt's Homepage  Reply with Quote
Good, open up R5 and R8. Then short circuit out R7 while replacing R4 with 680ohm and R6 with 560ohm. Adjust R2 at 'high voltage cut off'

awotol
www.simplecircuitsandprojects.com
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erki112
Apprentece

11 Posts

Posted - Mar 17 2011 :  2:46:13 PM  Show Profile  Reply with Quote
im not good in enghlish,but do i have to remove R5 and R8.and bridge R7.and replace R4 with 680 ohm 2w resistor.and R6 with 560 ohm 1/4w resistor. and finaly set pot to the max and test
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awt
Apprentece

Nigeria
9 Posts

Posted - Mar 17 2011 :  3:17:17 PM  Show Profile  Visit awt's Homepage  Reply with Quote
Yeah! you are correct, but 2W is not needed for R4. 680ohm,0.5W is ok for R4.

awotol
www.simplecircuitsandprojects.com
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awt
Apprentece

Nigeria
9 Posts

Posted - Mar 17 2011 :  3:58:16 PM  Show Profile  Visit awt's Homepage  Reply with Quote
it doesn't matter, it will work. i only suggested that one with lesser wattage to reduce the cost.

awotol
www.simplecircuitsandprojects.com
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