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 Low battery cutoff for Inverter with 4047 ic		  New Topic  Reply to Topic
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okpom
New Member

Nigeria
2 Posts
Posted - Jul 07 2015 :  10:13:33 PM  Show Profile  Reply with Quote
Please Sir, I would like to know the exact circuit that I can use to shut down my inerter when the battery is below 10v and which of the ic pin should I connect it? I used 4047ic.

Thanks.

Aaron Cake
Administrator

Canada
6718 Posts
Posted - Jul 08 2015 :  10:17:22 AM  Show Profile  Visit Aaron Cake's Homepage  Send Aaron Cake an ICQ Message  Send Aaron Cake a Yahoo! Message  Reply with Quote
Looking at the datasheet, that chip doesn't have any capability of sensing supply voltage.

Therefore you need an additional circuit.

An op-amp set up as comparator would be the most stable choice and have some adjustability.

http://www.renesas.eu/edge_ol/engineer/03/index.jsp

Then use the output to bring the "enable" pin of the 4047 high/low/whatever state stops the chip.
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audioguru
Nobel Prize Winner

Canada
4218 Posts
Posted - Jul 11 2015 :  9:00:08 PM  Show Profile  Reply with Quote
The inverter with the CG4047 IC that I fixed is at the Electronics-lab website forum, not here. In that forum there is a circuit to stop the inverter when the battery voltage becomes too low.
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