Aaron's Homepage Forum
Aaron's Homepage Forum
Home | Profile | Register | Active Topics | Members | Search | FAQ
 All Forums
 Electronics
 Basic Electronics
 Circuit to be manufactured

Note: You must be registered in order to post a reply.
To register, click here. Registration is FREE!

Screensize:
UserName:
Password:
Format Mode:
Format: BoldItalicizedUnderlineStrikethrough Align LeftCenteredAlign Right Horizontal Rule Insert HyperlinkInsert EmailInsert Image Insert CodeInsert QuoteInsert List
   
Message:

* HTML is OFF
* Forum Code is ON
Smilies
Smile [:)] Big Smile [:D] Cool [8D] Blush [:I]
Tongue [:P] Evil [):] Wink [;)] Clown [:o)]
Black Eye [B)] Eight Ball [8] Frown [:(] Shy [8)]
Shocked [:0] Angry [:(!] Dead [xx(] Sleepy [|)]
Kisses [:X] Approve [^] Disapprove [V] Question [?]

   Insert an Image File (GIF, JPG, JPEG, BMP, ZIP, PNG)
   

T O P I C    R E V I E W
irgreatinnovations Posted - Dec 16 2009 : 11:03:40 PM
I am looking for the infrared switch circuit to be built.

http://www.aaroncake.net/Circuits/IR_Remote_Switch_Circuit.asp

we need around 50 of them.

we would also like to have it power 5 volt USB port

Anyone interested in quoting a price, please contact me gklein@irgreat.com
2   L A T E S T    R E P L I E S    (Newest First)
irgreatinnovations Posted - Dec 17 2009 : 3:51:13 PM
Thank you for the information. Anyone interested in building 50 of them?
Aaron Cake Posted - Dec 17 2009 : 09:37:47 AM
Powering a USB port directly would require major changes to the circuit. The circuit is designed to operate on AC voltage, hence the simple zener diode power supply and TRIAC used to switch.

In order to make the circuit safely power a USB port (the basic supply included in the circuit is NOT isolated) then the power supply would need to be reworked to use a small transformer, and a regulator (like the 7805) would need to be used to provide appropriate current to a USB port @ 5V and to power the circuit. The TRIAC would need to be switched out with a simple pass transistor, U3 could be eliminated and the Q output of U3 would need to be inverted. Basically, an entirely different circuit after the right side of U3.

Aaron's Homepage Forum © 1995-2020 AARONCAKE.NET Go To Top Of Page
This page was generated in 0.05 seconds. Snitz Forums 2000