| T O P I C R E V I E W |
| Robert91_101 |
Posted - Apr 22 2012 : 11:12:22 PM
Hi, I simulated this inverter http://www.electronica2000.com/inversores/inversor-400-600w.htm in the PSPICE software. This is a based circuit of the one that is in this web http://www.aaroncake.net/circuits/inverter.asp.
That's how the simulation went. I want to know if this is the right output for this circuit, if not, what am i doing wrong?
Thanks so much, and sorry about my english.
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| 2 L A T E S T R E P L I E S (Newest First) |
| wasssup1990 |
Posted - Apr 25 2012 : 02:43:52 AM
Hi John, long time no type.
I'm curious if anyone out there has tried this:
1) Get an ordinary pure-sine inverter.
2) Get a few grid tie inverters.
3) Parallel the outputs of 1 and 2.
4) Power up 1.
5) Power up all of 2, sequentially.
6) Connect loads to the output and test to see if you are able to get the summed power output of all inverters.
The reason why you need 1 is because the grid tied inverters need to sense a voltage that is present on their outputs in order for them to work. It's an inbuilt safety feature to protect both the end-user and power-line maintenance crews.
I don't know of anyone who has tried this. I think it should theoretically be possible. It's like an upgradable inverter solution, on the cheap. Not very energy efficient, as these types of inverters usually only guarantee >80% efficiency. I designed an inverter achieving >95%.
Johnny
EDIT:
Sorry to the OP if I have hijacked your thread, but your question has been asked so many times and the answer has always been the same to all those who came before you; that inverter design sucks! Even if you managed to get such a simple and crude design to work, you'd be getting sub 80% efficiency for sure, which in a way, defeats the purpose of a power converting device such as an inverter.
Words of advice:
If you ever want to make an extremely compact, sub 300W inverter, use the boost converter topology. This topology is one of the most simple and efficient types you could use in the DC-DC converter stage of a modernly designed inverter. The amount of copper used in the primary magnetic device (inductor) is, by design kept to a minimum, which negates the need for a secondary coil to couple the magnetic energy (then called a transformer). What this means is the electric current has less copper to flow through, thus higher efficiency and cooler operation leading to a more compact design. I hope that's clear.
I have found this website to be a good sanity check for my designs:
http://schmidt-walter.eit.h-da.de/smps_e/smps_e.html
I hope you, or at least someone out there can find this info useful.
Johnny |
| audioguru |
Posted - Apr 24 2012 : 12:12:17 PM
The project DOES NOT WORK because it is too simple!
The emitter-base junctions of the transistors have avalanche breakdown which wastes most of the small amount of power the project produces which blows up the capacitors.
The base current for the transistors is much too low for a power inverter then the output power is very low.
It does not have any voltage regulation so its output voltage changes when loaded and as the battery runs down.
It does not have anything to disconnect the inverter when the battery gets low so the battery is destroyed.
Your simulation shows it running at less than 1Hz instead of at 60Hz. Then it frequently stops then starts then starts then stops. The transformer does not work at less than about 50Hz. |
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